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10m °ø±â¼ÒÃÑ(³²)
1À§ µ§ ¸¶ Å© Peter Thuesen 592+102.1=694.1
2À§ ±¹¹ÎÀºÇà ÀÓ ¿µ ¼· 588+102.9=690.9
3À§ ±¹¹ÎÀºÇà ±è ´ë ¼± 588+102.3=690.3

10m °ø±â¼ÒÃÑ(¿©)
1À§ ±¹¹ÎÀºÇà ¹Ú Àº °æ 396+104.0=500.0
2À§ µ§ ¸¶ Å© Anette Jensen 396+102.1=498.1
3À§ ±¹¹ÎÀºÇà ±è ¼± È­ 395+100.8=495.8