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´Üü 1À§ Ä¡¾Ç°í Á¤Áö±Ù,ÀÌÈñ¼®,¹ÚÁö¿µ,À̼öÇö 1762
´Üü 2À§ ´ë±¸Ã¼°í ±èÁ¤¿±,±èÇöµ¿,±èµµÈ¯,¹Ú¼ºÁø 1760
´Üü 3À§ Ãáõ½Ç°í ½Åµ¿¼º,ÇÔŽÄ,Á¤ÀçÈñ,¾ÈÀ缺 1758
°³ÀÎ 1À§ °æ±âü°í °­Ã¢¿ì 595 + 100.3 = 695.3 (º»)´ëȸŸÀÌ
°³ÀÎ 2À§ ´ëÀüü°í Á¤±¸Çù 593 + 100.8 = 693.8
°³ÀÎ 3À§ Ä¡¾Ç°í Á¤Áö±Ù 591 + 100.8 = 691.8

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°³ÀÎ 1À§ ÁßÆòÁß ±èÇöÁØ 568
°³ÀÎ 2À§ ¾ð³²Áß À̽ÂÈÆ 558

¡ã³²´ëºÎ 50m ¼ÒÃѺ¹»ç
´Üü 1À§ µ¿±¹´ë ÀÌÁ¾½Å,±èÇý¼º,±èÇüÅë,À̱¤Áø 1751 ´ëȸ½Å/1745
´Üü 2À§ °æ³²´ë ±ÇÁØö,¾ÈÁØö,Çã´ëÈÆ,À̼º¹Î 1750 ´ëȸ½Å/1745
´Üü 3À§ °æÈñ´ë ±èÀαâ,Á¤È¸À±,ÀÌ°æÅ 1748 ´ëȸ½Å/1745
°³ÀÎ 1À§ °æ³²´ë ±ÇÁØö 591 + 99.0 = 690.0 (º»)´ëȸ½Å/586 (°á)´ëȸ½Å/688.4
°³ÀÎ 2À§ ÇѼ­´ë ÃÖÇÏ´Ã 590 + 98.7 = 688.7 (º»)´ëȸ½Å/586 (°á)´ëȸ½Å/688.4
°³ÀÎ 3À§ Çѱ¹Ã¼´ë Á¤Àç½Â 586 + 101.2 = 687.2 (º»)´ëȸŸÀÌ

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´Üü 1À§ »ó¹« ÃÖ¿µÀü,±èÇи¸,ÇÑÁø¼·,¼­Ã¶¹Î 1769
´Üü 2À§ ±â¾÷ÀºÇà ³²ÇüÁø,À¯ÀçÁø,ä±Ù¹è 1765
´Üü 3À§ â¿ø½Ãû ¹è¼º´ö,õ¹ÎÈ£,¼Õ¼ºÃ¶ 1748
°³ÀÎ 1À§ KT ÃÖº´¿ì 595 + 102.6 = 697.6 (º»)´ëȸ½Å/594 (°á)´ëȸ½Å/695.1
°³ÀÎ 2À§ ´ã¾ç±ºÃ» ³²»êÈ£ 595 + 102.3 = 697.3 (º»)´ëȸ½Å/594 (°á)´ëȸ½Å/695.1
°³ÀÎ 3À§ ±â¾÷ÀºÇà ³²ÇüÁø 596 + 101.2 = 697.2 (º»)´ëȸ½Å/594 (°á)´ëȸ½Å/695.1

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´Üü 1À§ Á¤¼±°í ±è¼±¾Æ,ÃÖ½ÂÈñ,±èÁø¿µ 1138 ´ëȸ½Å/1136
´Üü 2À§ °æ±âü°í ¹ÚÁÖÈñ,ÀåºÎ°æ,À¯ÁöÈñ,Á¤ÁÖ¸® 1132
´Üü 3À§ ´ëÀüü°í ¿ÀÀ¯³ª,±è¹ÎÁø,±è¼ö¿¬,½Å´Ù¿µ 1127
°³ÀÎ 1À§ Á¤¼±°í ±è¼±¾Æ 391 + 101.4 = 492.4 (º»)´ëȸ½Å/384 (°á)´ëȸ½Å/484.8
°³ÀÎ 2À§ °­¿øü°í À±º¸¹è 384 + 101.4 = 485.4 (º»)´ëȸŸÀÌ (°á)´ëȸ½Å/484.8
°³ÀÎ 3À§ ¼­»ê¿©°í ÃÖº¸¹è 379 + 98.4 = 477.4

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°³ÀÎ 1À§ ÀÎõ´ë ¹Ú±ÔÇÐ 572 (º»)´ëȸ½Å/570
°³ÀÎ 2À§ ÀÎõ´ë ±èÁ¾·ü 570 (º»)´ëȸŸÀÌ
°³ÀÎ 3À§ ÀÎõ´ë À̱⼺ 560

¡ã³²ÀÏ¹Ý ¼¾ÅÍÆÄÀ̾î±ÇÃÑ
´Üü 1À§ KT ¹Úº´ÅÃ,È«¼ºÈ¯,ÀÌ»óÇÐ 1745
´Üü 2À§ »ó¹« ±è¼ºÁØ,±èÁøÀÏ,¾çÅ层 1728
´Üü 3À§ ³ë¿ø±¸Ã» ȲÀ±»ï,Â÷»óÁØ,¼Õ¿µ°¢ 1726
°³ÀÎ 1À§ KT ¹Úº´Åà 585
°³ÀÎ 2À§ KT È«¼ºÈ¯ 583
°³ÀÎ 3À§ ³ë¿ø±¸Ã» ȲÀ±»ï 581

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´Üü 1À§ ȯÀÏ°í ¹Ú±Ô»ó,ÃÖ¿ëÈÄ,±èÅ¿ë,±èÀÇÁ¾ 1720
´Üü 2À§ ¼­¿ï°í ¾ÈÇöÁø,±èÁØÈ«,Àü¿ìºó,ÃÖ¼ºÈÆ 1710
´Üü 3À§ ¼­¿ïü°í °í°æ¿í,±è¿µ±â,±è¿µ¼ö,ÀÓº´Âù 1693
°³ÀÎ 1À§ ȯÀÏ°í ¹Ú±Ô»ó 578
°³ÀÎ 2À§ ȯÀÏ°í ÃÖ¿ëÈÄ 577
°³ÀÎ 3À§ ȯÀÏ°í Á¶Âù¿µ 577

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°³ÀÎ 1À§ Áø¿µÁ¤º¸°ø°í ÀÌÁ¾ÁØ 111 + 21.0 = 132.0 (º»)´ëȸ½Å/99 (°á)´ëȸ½Å/118.0
°³ÀÎ 2À§ Ÿª°í À̼º±Ô 112 + 20.0 = 132.0 (º»)´ëȸ½Å/99 (°á)´ëȸ½Å/118.0
°³ÀÎ 3À§ ÅëÁø°í À̵¿ÇÏ 111 + 19.0 = 130.0 (º»)´ëȸ½Å/99 (°á)´ëȸ½Å/118.0

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°³ÀÎ 1À§ °æ³²´ë Á¶¿ë¼º 113 + 22.0 = 135.0
°³ÀÎ 2À§ °æ±â´ë °­Çö¼® 110 + 20.0 = 130.0
°³ÀÎ 3À§ °æÈñ´ë ÃÖµ¿±â 91 + 19.0 = 110.0

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´Üü 1À§ ¿ï»êºÏ±¸Ã» À±µ¿±Ù,ȲÁ¤¼ö,Á¶±¤¼ö 346 ´ëȸ½Å/345
´Üü 2À§ ±èÆ÷½Ãû ±èâ³â,±èÇÏ¿¬,¹è±æȯ,¿øº´¼® 345 ´ëȸŸÀÌ
°³ÀÎ 1À§ ±èÆ÷½Ãû ±èâ³â 120 + 24.0 = 144.0 (º»)´ëȸ½Å/118 (°á)´ëȸ½Å/142.0
°³ÀÎ 2À§ ¿ï»êºÏ±¸Ã» À±µ¿±Ù 118 + 24.0 = 142.0 (º»)´ëȸŸÀÌ (°á)´ëȸŸÀÌ
°³ÀÎ 3À§ ¿ï»êºÏ±¸Ã» ȲÁ¤¼ö 116 + 23.0 = 139.0